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KW?g$0yӭ4m~ȥ3C!ʁw$HNò͐q~ Zy9!窄Mq(xZC7;>g@'I_JiЂ ӐxN_ds%~ݽ91N\x"CkCp2_)sh4ŝahE}eJ/\an;V,X$Q:x'u`lr8\ K`6Βg k3K.km:vq@/Sv=-? 6/] 6-C(Ic J=aOLx r&SU* `2ХGrP%j;3,驌: V?܇ri dmœv^s%$=2 uD<UH3|1[!%)p#)|r2>\`Y{ff` R>&- {p_/̴>?" dd@,|?" dd@   " @ ` n?" dd@   @@``PR    @ ` ` p>> f(    6ܔ  `}  T Click to edit Master title style! !  0  `  RClick to edit Master text styles Second level Third level Fourth level Fifth level!     S  08 ^ `  >*  0  ^   @*  0 ^ `  @*H  0޽h ? 3380___PPT10.t~ Default Design40 0 .(   x   <A ?? x   <A ??    0 ) E EXAMPLE 1 0   Bh) a#Finding the Area of a Parallelogram"$0$  <)}m,$@0 @SOLUTION 0   <&)n,$0 9=0  </)^y~,$0 ;A0  <9)^~,$0 Rbh40   6D)x v ,$0 p2Write the formula for the area of a parallelogram."30 23s  <N) k ,$0 9=0  <X) y ,$ 0 :100  Ba) ,$0 E Simplify. 0 s  6k)} p:@,$@0 >ANSWER0(  B@v)k:y,$0 2The area of the parallelogram is 10 square meters.430!  B)@@`,$0 a)Find the area of the parallelogram shown.*0*  0A? Gw,$D0  <) n ,$ 0 9=0  <@) I ,$ 0 Q5 200  B,)  ,$ 0 Substitute 5 for b and 2 for h. 0 sssssssss  B)  ,$ 0 F "0H  0޽h ? ̙33!!___PPT10}!+:cD' = @B D' = @BA?%,( < +O%,( < +D' =%(%(Du' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =%(DM' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D ' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(Ds' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(+H+0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 +0   @ (  x  <A ??    B0@,$0 e-Find the area of the described parallelogram..0.  B,Y ,$0 $1. base = 6 in., height = 10 in.%0  0B E EXAMPLE 3 0   B  Rfor Examples 2 and 3"0x  <A ??"   <d!G KGUIDED PRACTICE 0   Bx+  K for Example 1"0)z : :    :: ,$D0   6\5}p : >ANSWER0   BT^N:  q60 in.2N0 a   BcN 0 ,$0 !2. base = 7 cm, height = 4 cm~"0z : :   ^ pp,$D0  6YN}p : >ANSWER0  B\xN:  X28 cm260 H  0޽h ? ̙33e ] ___PPT10= +]Dy ' = @B D4 ' = @BA?%,( < +O%,( < +Da' =%(%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(DA' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D4' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(DA' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D4' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(++0+0 ++0+0 ++0+ 0 +$<0 ` (    </30 ,$ 0 a45 b 960x  <A ?? x  <A ??    0 E EXAMPLE 2 0   B ZFinding an Unknown Dimension"0  6} ,$@0 >ANSWER0  <4r / ,$ 0 ub 45 9 H0 #   <l` Y9 ,$ 0 9=0   Bt  ,$0 ^"Write a related division equation. #0#s   <  ,$0 Nb 5* 0   < P0 ,$0 9=0   Bȡ  ,$0 E Simplify. 0 s  Bp j ,$0 jThe base is 5 centimeters.40   <x}O,$@0 @SOLUTION 0   B}\,$0 n2Write the formula for the area of a parallelogram. 303s  <\*tbK,$0 ;A0  < 4z:,$0 <bh0  <=V6,$0 9=0  <@GP06 ,$ 0 9=0  BQ(,$0 D "0  BZ ,$ 0  Substitute 45 for A and 9 for h.!0 ssssssssssu  6XqAG,$0 gThe area of a parallelogram is 45 square centimeters and the height is 9 centimeters. What is the base?Xh0 2&H  0޽h ? ̙33<&4&___PPT10&+`dcD"' = @B D!' = @BA?%,( < +O%,( < +Da' =%(%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =%(DM' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D ' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(Ds' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(Ds' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(++0+0 ++0+0 ++0+0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 +^0 t l p&& (  x  <A ?? x  <A ??    0>v E EXAMPLE 3 0   BIvt  qEstimating AreaF0   <v =,$0 `1" b<0##  <[v  ,$0 ;=0  <v 0 ,$ 0 ?92(3.6)0   <,v 9,$ 0 ;=0   <v0P,$ 0 ;b0   <hv' G,$ 0 =331.20   <+v U,$ 0 `1" h<0##   <5v kL,$0 ;=0  <v ,$0 ?92(0.9)0  <v}^6,$0 ;=0  <v-cM,$0 ;h0  < qv-M,$0 <82.80  0A?@ P,$D0  6t't  ,$0 GSTEP 1 Use the scale to find the base b and the height h in kilometers.H0O  67t(,l ,$0 {A parallelogram can be used to approximate the shape of Lake Erie. Use the map and scale to estimate the area of Lake Erie.|0 2|  <At}P ,$@0 @SOLUTION 0   <Kt T ,$0 =92 km0B  c $D  ,$@0  <Wtg  ,$0 ;=0  <`t  ,$0 >3.6 cm0B  c $D ,$@0  <djt ,$0 Jb km*0  <$ut ) ,$0 <1 cm0  <Xt p ,$0 =92 km0B  c $D o ,$@0  <tm kL ,$0 ;=0   <đt ; ,$0 >0.9 cm0B ! c $D /o ,$@0 " <pt LE ,$0 Jh km*0 # <t  # ,$ 0 <1 cm0 $ <Ĕt\#,$@0 A Geography 0  % B"t d - ,$!0 <Base0 & Bt ]* ,$"0 >Height0H  0޽h ? ̙33> >___PPT10=+isD7' = @B Di7' = @BA?%,( < +O%,( < +D' =%(%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D0-' =%(D,' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*!%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*"%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*#%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*&%(+ +0+0 ++0+0 ++0+0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+0 ++0+ 0 ++0+"0 ++0+#0 ++0+$0 ++0+%0 ++0+&0 +,0  Z(   x   <A  ??  x   <A  ??     0k E EXAMPLE 3 0   Bܲkt  qEstimating AreaF0   B4kWv,$0 r&STEP 2 Estimate the area of Lake Erie.0'0   < k,$0 ;=0  <8k6,$0 <bh0  <wk^~,$ 0 ;=0  <$kZz,$0 ?330(80)0  <kn,$ 0 ;=0  <hk[{,$ 0 >26,4000  Bkn,$0 n2Write the formula for the area of a parallelogram. 303s  6 kp}}*,$0 n2Round the base and the height to the nearest tens. 303s  Bнkm g,$ 0 E Simplify. 0 s  6 k} [%@ ,$@ 0 >ANSWER0.  Bk\ 2`| ,$0 8The area of Lake Erie is about 26,400 square kilometers.490  <Hk,$0 ;A0H  0޽h ? ̙33wo___PPT10O+qD[' = @B D' = @BA?%,( < +O%,( < +Da' =%(%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D ' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(Ds' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(Ds' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 ++0+ 0 +#0 $(  $x $ <A  ??   $ 0@$ E EXAMPLE 3 0  $ B($  Rfor Examples 2 and 3"0x $ <A  ??"   $ <~$G KGUIDED PRACTICE 0 $ B$ ? Rfor Examples 2 and 3"0? $ B$c,$0 1In Exercises 3 and 4, find the unknown dimension.L20   $ 6x$c,$0 G?3. Area of parallelogram = 72 in.2, base = 12 in., height = ? @0  B  $ c $D',$D0  $ 6$} ,$@0 >ANSWER0  $ Bp$Pp,$0 =6 in.0  $ 6h$} @,$@ 0 >ANSWER0 $ B<$pN,$ 0 =25 mm0  $ BLU X{ ,$0 e;4. Area of parallelogram = 125 mm2, height = 5 mm, base = ?<0 B $ c $D g ,$D0H $ 0޽h ? ̙33___PPT10+{{D' = @B D' = @BA?%,( < +O%,( < +Da' =%(%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =%(Du' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* $%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* $%(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* $%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* $%(D' =%(Du' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* $%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*$%(++0+$0 ++0+ $0 ++0+ $0 ++0+ $0 ++0+ $0 ++0+$0 ++0+$0 +J0 B : ( (  (x ( <A  ??   ( 0Ӳ E EXAMPLE 3 0  ( B  Rfor Examples 2 and 3"0x ( <A ??"  ( < G KGUIDED PRACTICE 0 ( BTŲ ? 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